Java If-Else | HackerRank solution by CodingHumans |

Java If-Else

Problem

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task

Given an integer, , perform the following conditional actions:
If  is odd, print Weird
If  is even and in the inclusive range of  2 to 5 ,
 print Not Weird
If  is even and in the inclusive range of  6 to 20 ,
 print Weird
If  is even and greater than 20, print Not Weird
Complete the stub code provided in your editor to print whether or not n is weird.
Input Format
A single line containing a positive integer,n .

Constraints

 1<=n <=100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: n=3
 n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n=24
n>24 and  is even, so it isn't weird. Thus, we print Not Weird.

Solution:

import java.util.*;
public class solutions{
    public static void main(String args[]){
        Scanner scan=new Scanner(System.in);
        int n=scan.nextInt();
        if(n%2==1 || (n>=6 && n <= 20)){
   System.out.print("Weird");
}else{
   System.out.print("Not Weird");
}
}

}